Question one

Question : A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.​ ___________________________________________ Answer :

 vi = 0 m/s 

vf = 88.3 m/s

 d = 1365 m 

                 Answer to be found :

 vf² = vi² + 2*a*d

  (88.3 m/s)² = (0 m/s)² + 2*(a)*(1365 m)

 7797 m²/s² = (0 m²/s²) + (2730 m)*a

 7797 m²/s² = (2730 m)*a 

 (7797 m²/s²)÷(2730 m) = a

  a = 2.86 m/s² 

vf = vi + axt

  88.3 m/s = 0 m/s + (2.86 m/s²)*t 

 (88.3 m/s)÷(2.86 m/s²) =t 

t = 30. 8 s

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